Sorry Libelium-Dev. But bear with me for a moment because I am going to go to calibrate the sensor soon and I would like to know if I am doing the right steps: -
I am trying to calibrate the TGS2611 Methane sensor as follows: -
[*] Find relationship from the Rs/Ro graph
[*] Estimate Rs when the concentration is equal to 5000 ppm
[*] Use this estimation as RL (right or wrong?)
Quote:
Step 1: Graph relationship
Since this graph is log of nature:
y1 = 1 , x1 = 5000
y2 = 2 , x2 = 1000
let Rs/R0 = y
we estimate the linear graph : -
log ( Rs/Ro ) = mlog(x) + log(b)
m = [ log(y2) - log(y1) ] / [ log(x2) - log(x1) ]
m = - [ log(2) / log(5) ]
log(b) = log(y) + [log(2) / log(5)]log(x) >>By rearranging the equation
log(b) = log(2)log(5000) / log(5)
.:. The linear relationship of the graph is: -
log(Rs/Ro) = - [ log(2) / log(5) ]log(x) + log(2)log(5000) / log(5) >> exact. no-rounding
The data-sheet from the manufacturer states the following: -
R(LOAD) - MINIMUM = 0.45 kOHMS
R(LOAD) - MAXIMUM = 100 kOHMS <<< specified by Libelium
Rs = 0.68k - 6.8k ohms (under stand. test conditions)
MY QUESTION IS:Since I figured out a relationship for the graph. How am I suppose to estimate the value of Rs? I see many problems especially since: -
[*] Ro
IS THE ACTUAL RESISTANCE of 5000 ppm concentration
[*] How is it possible to estimate Rs without getting V(LOAD) and R(LOAD) in the first place?
[*] Are you suppose to use a recommended R(LOAD) first ?
Please explain thoroughly how you would estimate Rs... I did the pleasure to post the relationship for you: -
Quote:
log(Rs/Ro) = - [ log(2) / log(5) ]log(x) + log(2)log(5000) / log(5)
-Thank you.